if you use ob_start with a callback function as a parameter, and that function changes ob string (as in example in manual) don't expect that ob_get_contents will return changed ob.
it will work as you would use ob_start with no parameter at all. So don't be confused.
ob_get_contents
(PHP 4, PHP 5)
ob_get_contents — Return the contents of the output buffer
说明
string ob_get_contents
( void
)
Gets the contents of the output buffer without clearing it.
返回值
This will return the contents of the output buffer or FALSE, if output buffering isn't active.
范例
Example#1 A simple ob_get_contents() example
<?php
ob_start();
echo "Hello ";
$out1 = ob_get_contents();
echo "World";
$out2 = ob_get_contents();
ob_end_clean();
var_dump($out1, $out2);
?>
上例将输出:
string(6) "Hello " string(11) "Hello World"
ob_get_contents
m227 ( at ) poczta dot onet dot pl
24-Feb-2005 10:53
24-Feb-2005 10:53
http://www.francescosaf.altervista.org
08-Feb-2005 06:04
08-Feb-2005 06:04
transfer image, another method (alternative to fsockopen or function socket) :
server(192.168.0.1)
makeimage.php
...........
...........
$nameimage="xxxx.jpg"
$comand=exec("plotvelocity.sh $nameimage $paramater1 $paramater2");
ob_start();
readfile($nameimage);
$image_data = ob_get_contents();
ob_end_clean();
echo $image_data;
unlink($nameimage);
Client (192.168.0.2)
$bild="images/newimage2.gif";
$host="192.168.0.1";
$url=file_get_contents("http://$host/makeimage.php?$querystring");
$fp = fopen("$bild", 'wb');
fwrite($fp, $url);
fclose($fp);
echo '<img src="'.$bild.'">';
naturally you can transfer whichever thing and not only images
